Implement linux amd64 step

This commit is contained in:
Derek Parker 2014-05-20 13:23:35 -05:00
parent 5b7f7d92a5
commit ea0ff20e16
4 changed files with 122 additions and 0 deletions

BIN
fixtures/testprog Executable file

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11
fixtures/testprog.go Normal file

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package main
import (
"fmt"
"time"
)
func main() {
time.Sleep(time.Second)
fmt.Println("Hello, World!")
}

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package proctl
import (
"fmt"
"os"
"syscall"
)
type DebuggedProcess struct {
Pid int
Regs *syscall.PtraceRegs
Process *os.Process
}
func NewDebugProcess(pid int) (*DebuggedProcess, error) {
err := syscall.PtraceAttach(pid)
if err != nil {
return nil, err
}
proc, err := os.FindProcess(pid)
if err != nil {
return nil, err
}
debuggedProc := DebuggedProcess{
Pid: pid,
Regs: &syscall.PtraceRegs{},
Process: proc,
}
_, err = proc.Wait()
if err != nil {
return nil, err
}
return &debuggedProc, nil
}
func (dbp *DebuggedProcess) Registers() (*syscall.PtraceRegs, error) {
err := syscall.PtraceGetRegs(dbp.Pid, dbp.Regs)
if err != nil {
return nil, fmt.Errorf("Registers():", err)
}
return dbp.Regs, nil
}
func (dbp *DebuggedProcess) Step() error {
err := syscall.PtraceSingleStep(dbp.Pid)
if err != nil {
return err
}
_, err = dbp.Process.Wait()
if err != nil {
return err
}
return nil
}

50
proctl/proctl_test.go Normal file

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package proctl
import (
"os/exec"
"testing"
)
func StartTestProcess() (int, error) {
cmd := exec.Command("../fixtures/testprog")
err := cmd.Start()
if err != nil {
return 0, err
}
return cmd.Process.Pid, nil
}
func TestStep(t *testing.T) {
pid, err := StartTestProcess()
if err != nil {
t.Fatal("Starting test process:", err)
}
p, err := NewDebugProcess(pid)
if err != nil {
t.Fatal("NewDebugProcess():", err)
}
regs, err := p.Registers()
if err != nil {
t.Fatal("Registers():", err)
}
rip := regs.PC()
err = p.Step()
if err != nil {
t.Fatal("Step():", err)
}
regs, err = p.Registers()
if err != nil {
t.Fatal("Registers():", err)
}
if rip >= regs.PC() {
t.Errorf("Expected %#v to be greater than %#v", regs.PC(), rip)
}
}